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Geometry 8 Online
OpenStudy (anonymous):

http://www.castlelearning.com/review/imagelibrary/PersonalImages/70/4150970/test%2023b.jpg find x

OpenStudy (anonymous):

just a sec I need to solve it

OpenStudy (anonymous):

ok thanks

OpenStudy (anonymous):

|dw:1418285122074:dw| use the pythagorian theorem

OpenStudy (anonymous):

d^2=a^2+h^2 c^2=h^2+b^2 a+b=8

OpenStudy (anonymous):

h^2=d^2-a^2 h^2=c^2-b^2 a+b=8

OpenStudy (anonymous):

the possible answers are 2 square root of 3, 4 square root of 3,4,and 6

OpenStudy (anonymous):

you can try to sunstitude them and check if one works

OpenStudy (anonymous):

d^2-a^2=c^2-b^2 a+b=8

OpenStudy (anonymous):

d^2-c^2=a^2-b^2 a+b=8

OpenStudy (anonymous):

also you can find h using area h*8=d*c

OpenStudy (anonymous):

(d+c)(d-c)=8*(a-b)

OpenStudy (anonymous):

I have no idea

OpenStudy (anonymous):

@SolomonZelman

OpenStudy (anonymous):

I now see that I'm stuck in it

OpenStudy (anonymous):

d^2=h^2+36

OpenStudy (anonymous):

just a sec I GOT IT!!!

OpenStudy (anonymous):

add two first equations and on the left side you will get a hypotenuse

OpenStudy (anonymous):

and

OpenStudy (anonymous):

d^2=a^2+h^2 c^2=h^2+b^2 result in d2+c2=2h2+a2+b2 a2+b2=36+4=40

OpenStudy (anonymous):

d2+c2=64 64=2h2+40

OpenStudy (anonymous):

h2=24/2=12

OpenStudy (anonymous):

h=sqrt12=sqrt(4*3)=2*sqrt3

OpenStudy (anonymous):

so the answer is \[2\sqrt3\]

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