Geometry
8 Online
OpenStudy (anonymous):
http://www.castlelearning.com/review/imagelibrary/PersonalImages/70/4150970/test%2023b.jpg
find x
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OpenStudy (anonymous):
just a sec I need to solve it
OpenStudy (anonymous):
ok thanks
OpenStudy (anonymous):
|dw:1418285122074:dw|
use the pythagorian theorem
OpenStudy (anonymous):
d^2=a^2+h^2
c^2=h^2+b^2
a+b=8
OpenStudy (anonymous):
h^2=d^2-a^2
h^2=c^2-b^2
a+b=8
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OpenStudy (anonymous):
the possible answers are 2 square root of 3, 4 square root of 3,4,and 6
OpenStudy (anonymous):
you can try to sunstitude them and check if one works
OpenStudy (anonymous):
d^2-a^2=c^2-b^2
a+b=8
OpenStudy (anonymous):
d^2-c^2=a^2-b^2
a+b=8
OpenStudy (anonymous):
also you can find h using area
h*8=d*c
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OpenStudy (anonymous):
(d+c)(d-c)=8*(a-b)
OpenStudy (anonymous):
I have no idea
OpenStudy (anonymous):
@SolomonZelman
OpenStudy (anonymous):
I now see that I'm stuck in it
OpenStudy (anonymous):
d^2=h^2+36
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OpenStudy (anonymous):
just a sec I GOT IT!!!
OpenStudy (anonymous):
add two first equations and on the left side you will get a hypotenuse
OpenStudy (anonymous):
and
OpenStudy (anonymous):
d^2=a^2+h^2
c^2=h^2+b^2 result in d2+c2=2h2+a2+b2
a2+b2=36+4=40
OpenStudy (anonymous):
d2+c2=64
64=2h2+40
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OpenStudy (anonymous):
h2=24/2=12
OpenStudy (anonymous):
h=sqrt12=sqrt(4*3)=2*sqrt3
OpenStudy (anonymous):
so the answer is \[2\sqrt3\]