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Mathematics 17 Online
OpenStudy (anonymous):

What is the equation of the graph below?

OpenStudy (anonymous):

OpenStudy (catlover5925):

do you have answer choices

OpenStudy (anonymous):

ya hold on one sec

OpenStudy (anonymous):

OpenStudy (catlover5925):

these are my note from 8th grade

OpenStudy (catlover5925):

id ont know if this will help cuz we only worked with them when the vertex was on the (0, 0) an i am in 10th grade now and never did this off the vertex of 0, 0

OpenStudy (anonymous):

Oh ok thanks for trying anyways. Your notes are somewhat helpful

OpenStudy (catlover5925):

ok nevermind idk sorry @perl

OpenStudy (anonymous):

its ok

OpenStudy (catlover5925):

@iGreen @nincompoop @bibby @zepdrix @Hero @ganeshie8

OpenStudy (anonymous):

@Hero @ganeshie8

OpenStudy (catlover5925):

@Data_LG2

OpenStudy (xventurientalex):

@chosenmatt

OpenStudy (anonymous):

vertex form of a quadratic equation is \(\sf y=a(x-h)^2+k\), where \(\sf (h,k)\) is the your vertex point (or the max/min point of the graph) , brb!

OpenStudy (anonymous):

now i'm back... so (h,k) is your minimum point from your graph, which is? (3, -2) so you'll have \( \sf y=a(x-3)^2-2\), not to find the value of \(\sf a\), take any point from your graph and plug it to the equation and solve for \(\sf a\) (:

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