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OpenStudy (anonymous):
OpenStudy (catlover5925):
do you have answer choices
OpenStudy (anonymous):
ya hold on one sec
OpenStudy (anonymous):
OpenStudy (catlover5925):
these are my note from 8th grade
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OpenStudy (catlover5925):
id ont know if this will help cuz we only worked with them when the vertex was on the
(0, 0) an i am in 10th grade now and never did this off the vertex of 0, 0
OpenStudy (anonymous):
Oh ok thanks for trying anyways. Your notes are somewhat helpful
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OpenStudy (anonymous):
@Hero @ganeshie8
OpenStudy (catlover5925):
@Data_LG2
OpenStudy (xventurientalex):
@chosenmatt
OpenStudy (anonymous):
vertex form of a quadratic equation is \(\sf y=a(x-h)^2+k\), where \(\sf (h,k)\) is the your vertex point (or the max/min point of the graph) , brb!
OpenStudy (anonymous):
now i'm back...
so (h,k) is your minimum point from your graph, which is? (3, -2)
so you'll have \( \sf y=a(x-3)^2-2\), not to find the value of \(\sf a\), take any point from your graph and plug it to the equation and solve for \(\sf a\) (: