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If 17% of the listeners of a radio station listen to it while they are at work, what is the approximate standard deviation of the sampling distribution of the proportion for samples of size 91? A. 7.8% B. 3.9% C. 1.8% D. 0.4%
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Use the formula \[\Large \sqrt{\frac{p(1-p)}{n}}\]
In this case, p = 0.17 n = 91
ok i did is D?
what result did you get?
numeric result
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it was 0.039and bunch of other numbers
convert that to a percentage (multiply the result by 100)
ex: 0.17 = 0.17*(100%) = 17%
ok so it would be 3.9377% and the closest answers is 4% so D? :)
read D again carefully
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Oh wow im an idiot sorry its B right?
yes B
thank you so much :D
np
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