Question

The tenth, eleventh, and twelfth terms of a sequence are shown in the table below:

Term number
10

11

12
Term
-34

-38

-42


Which of the following shows the first five terms of the sequence?

Answer 1

-2, 2, 6, 10, 14

2, -2, -6, -10, -14

-2, -6, -10, -14, -18

2, 6, 10, 14, 18

Answer 2

@ganeshie8

Answer 3

@iambatman

Answer 4

Anybody?

Answer 5

@Mertsj

Answer 6

I think it could be C...

Answer 7

Do you see that term 11 is term 10 minus 4 and term 12 is term 11 minus 4?

Answer 8

Yeah?

Answer 9

Would that mean it would be D?

Answer 10

Since all of the terms are being subtracted?

Answer 11

So use:
\[a _{n}=a _{1}+(n-1)d\]

Answer 12

??? Erm, I really have not learned this too well... My algebra teacher is terrible

Answer 13

The 12th term is -42 so let n = 12, common difference is -4. Solve for a_1

Answer 14

Could you possibly explain how to incorporate my items into the equation?

Answer 15

Oh, ok...

Answer 16

What is a_12?

Answer 17

an=a1+(12−1)d well, would it be 11?

Answer 18

\[a _{12}=a _{1}+(12-1)(-4)\]

Answer 19

So am I right? Is it 11?

Answer 20

\[-42=a _{1}+(11)(-4)\]

Answer 21

Solve for a_1

Answer 22

Oh, I see.. SO then, do I have to arrange the numbers in order?

Answer 23

would a_1 be 3?

Im sorry, this is just difficult... :/

Answer 24

What is 11(-4)

Answer 25

-44

Answer 26

?

Answer 27

Add that to both sides of the equation.

Answer 28

That is, add 44 to both sides of the equation.

Answer 29

Ok, so would it look like this 44 + −42=a1+(11)(−4) + 44?