What is the slope-intercept form of the function described by this table?

y = x +

Question

What is the slope-intercept form of the function described by this table?

y =      x +

anonymous · Answer

attachment

anonymous · Answer

Helo! The formula for this is

$$\frac{ x2-x1 }{ Y2-Y1 } So your equation \right now is \frac{ 2-1 }{  }$$

anonymous · Answer

Oh what why did it do that? Okay lets try this again
$$\frac{ 2-1 }{ 7-2 }$$

anonymous · Answer

What do you get if you solve this?

anonymous · Answer

1/5

anonymous · Answer

Yes! Thats your slope! The formula is 

$$y=mx+b$$

M=slope B=y intercept. Can you fill this out with this information?

anonymous · Answer

NO

anonymous · Answer

@DanJS  can u help me on this please?

anonymous · Answer

hey Abhilash11  do u know how to do this:)?

anonymous · Answer

@MARC_ can u help?

directrix · Answer

@20075    The slope of the line is 5/1 or 5.

Take two points, say (1,2) and (2,7)

The slope is (7 - 2)/(2 -1) = 5/1 = 5

It will be the same regardless of which two points in the chart you use to compute it.

y = mx + b is the slope-y-intercept form for a line.

So far, we have y = 5x + b

(1,2) is a point on the line so it has to "satisfy" the equation.

2 = 5*1 + b
2 = 5 + b
b = -3

Now we can complete this: y = 5x + b

y = 5x - 3
It is the slope-intercept form of the function described by this table.