Question

Find the derivative of f(x) = 6x + 2 at x = 1.

Answer 1

@ganeshie8 Do i just square the x as the others

Answer 2

the derivative of 6x + 1 is a constant,

Answer 3

\[\frac{ d }{ dx }(6x + 2) = 6\]

Answer 4

Then i plug in the 1

Answer 5

for all values of x,

y ' = 6

It is a horizontal line. No plug in needed.

Answer 6

Oh okay so the answer is 6 then, just ignore the 1?

Answer 7

the graph of the derivative is a horizontal line at y = 6

so for any x value you look at, the y value will be 6

Answer 8

in other words
y = 0(x) + 6

Answer 9

y(1) = 0(1) + 6 = 6

Answer 10

Oh okay so it is 6 since x is 0

Answer 11

@DanJS

Answer 12

no the slope is zero, it is a horizontal line at y = 6

y = m*x+6

Where m is the slope = 0

so you see for any x value you choose, in this case 1,

y = 0*(1) +6

Answer 13

Im confusd on what the answer is

Answer 14

the answer is 6

Answer 15

is it 1 or 6?

Answer 16

Do you see that if you have a horizontal line graphed at y = 6
no matter the x value, the y value is 6

Answer 17

So any question in that form the answer is the y vallue?

Answer 18

The position of an object at time t is given by s(t) = -8 - 9t. Find the instantaneous velocity at t = 1 by finding the derivative.
The answer would be -8 since it is thte y value?

Answer 19

you need to find the derivative first. That is the important part.
In this case, the derivative is just a constant number 6.

Answer 20

@DanJS

Answer 21

\[\frac{ d }{ dt }[-8-9t]\]

Answer 22

then do the y=mx+b

Answer 23

what is the derivative first?

Answer 24

im honestly confused ,what is the equation

Answer 25

\[\frac{ d }{ dx }x ^{n}=n*x ^{n-1}\]

Answer 26

The power rule is what you would use

Answer 27

The derivative of [-8-9t] is

-9

so for t=1, the instantaneous velocity is -9

Answer 28

oh okay

Answer 29

thank you!!!!!!