Find the indicated limit, if it exists. limit of f of x as x approaches 8 where f of x equals x plus 10 when x is less than 8 and f of x equals 10 minus x when x is greater than or equal to 8
x+10 x less than 8 10-x x greater than or equal to 8
hey you should start using latex
i have a few questions like this and really want to know how to solve problems like these
latex?
\[f(x) = \left\{\begin{array}{} x+10&:& x \lt 8 \\10-x&:&x\ge 8\end{array}\right.\] like this ?
yes
you want to find \(\lim\limits_{x\to 8} f(x)\)
but it has lim with x-->8 under it
You have to check if f is continuous at 8 and -8
we say the limit exists if you converge to the same value from both left and right sides of 8
plugin x=8 into both the given pieces of function the limit exists if you get same value
so 18 x less than 8 and 2 x greater than or equal to 8
they are both false
Well they have to equal otherwise the limit does not exist
by equalling each other you mean like getting 18 and 18 when I plug in the 8
yes
oh okay thankssss aton !
so for Find the indicated limit, if it exists. limit of f of x as x approaches 0 where f of x equals 5 x minus 9 when x is less than 0 and the absolute value of the quantity 2 minus x when x is greater than or equal to 0 the limit would not exist right?
@ganeshie8
i have gotten that for all my answers in my work
yes limit does not exist because the left and right limits converge to different values. graph makes it easy to see http://gyazo.com/e148f280b022d5186dc7258c1e017731
Oh okay cause out of my 5 hw questions I have gotten so
thanks again!
Notice as you approach 8 from left, the function goes to 18 but when you approach 8 from right, the function goes to 2 they dont converge to same value so we say \(\lim\limits_{x\to 8} f(x) = \text{Does Not Exist}\)
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