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Mathematics 10 Online
OpenStudy (anonymous):

i really need help with this math problem

OpenStudy (anonymous):

OpenStudy (anonymous):

@iGreen

OpenStudy (anonymous):

Hello, are you able to set it up?

OpenStudy (anonymous):

We have to evaluate \[\frac{ x }{ y }\] and are given \[x = \frac{ 2 }{ 3 },~~ \text{and}~~ y =\frac{ 6 }{ 7 }\]

OpenStudy (anonymous):

So give me your best attempt at setting it up and we will go from there :)

OpenStudy (anonymous):

well im not good with this one so >>.

OpenStudy (anonymous):

That's alright, just give it a try, don't be afraid to mess up, I don't judge, I'm here to help!

OpenStudy (anonymous):

Can you do \(x\cdot y\)?

OpenStudy (anonymous):

Can you find \(1/y\)?

OpenStudy (anonymous):

y=9x over 7 :< idk

OpenStudy (anonymous):

does anyone know the answer ??

OpenStudy (anonymous):

i wish i knew it .:0

OpenStudy (anonymous):

Not quite, all you really have to do is plug x where x is in the equation x/y and do the same thing for y. So, \[\huge \frac{ x }{ y } \implies \frac{ \left( \frac{ 2 }{ 3 } \right) }{ \left( \frac{ 6 }{ 7 } \right)}\]

OpenStudy (anonymous):

Don't worry about the answer right now, try understanding the process and what it's asking.

OpenStudy (anonymous):

okay :) so i need to ..

OpenStudy (anonymous):

So, when you first learn about fractions, do you remember what they tell you when you want to divide them?

OpenStudy (anonymous):

yes :)

OpenStudy (anonymous):

Alright, so what do they tell you? :)

OpenStudy (anonymous):

well don't you have to divide both ,..... right

ganeshie8 (ganeshie8):

they tell you about pies and cakes to increase your appetite

OpenStudy (anonymous):

well now i know its either A OR B correct ?

OpenStudy (anonymous):

^ lol, but I was looking for, when you divide fractions, you flip it and multiply, so \[\huge \frac{ x }{ y } \implies \frac{ \left( \frac{ 2 }{ 3 } \right) }{ \left( \frac{ 6 }{ 7 } \right)} \implies \frac{ 2 }{ 3 } \times \frac{ 7 }{ 6 }\]

OpenStudy (anonymous):

Are you able to finish it off?

OpenStudy (anonymous):

flip the second fraction*

OpenStudy (anonymous):

im really slow in math

ganeshie8 (ganeshie8):

after that they feed you the poison : divding two complex fractions is same as multiplying the first fraction and reciprocal of second fraction

OpenStudy (anonymous):

so i think i got it . its B yea , nO?

OpenStudy (anonymous):

It's ok if you're "slow" at math, it requires practice and the first step is to attempt the problem. How did you get B?

OpenStudy (anonymous):

well when i multiply the fractions it = 4 over 7 so thats just a bad guess

ganeshie8 (ganeshie8):

thats a very good wrong guess, you just forgot flipping the second fraction

ganeshie8 (ganeshie8):

\[\huge \frac{ x }{ y } \implies \frac{ \left( \frac{ 2 }{ 3 } \right) }{ \left( \frac{ 6 }{ 7 } \right)} \implies \color{red}{\frac{ 2 }{ 3 } \times \frac{ 7 }{ 6 }} \]

ganeshie8 (ganeshie8):

can you work that multiplication ? to multiply two fractions, you just multiply numerators and denominators separately

ganeshie8 (ganeshie8):

\[\large \dfrac{a}{b}\times \dfrac{c}{d} = \dfrac{a\times c}{b\times d}\]

OpenStudy (anonymous):

okay step by step first thing . i want to get this question right :)

OpenStudy (anonymous):

@NicholausBlackmon

ganeshie8 (ganeshie8):

\[\huge \begin{align} \frac{ x }{ y } \implies \frac{ \left( \frac{ 2 }{ 3 } \right) }{ \left( \frac{ 6 }{ 7 } \right)} &\implies \color{red}{\frac{ 2 }{ 3 } \times \frac{ 7 }{ 6 }}\\~\\~\\ &\implies \color{red}{\dfrac{2\times 7}{3\times 6}} \end{align}\]

ganeshie8 (ganeshie8):

now it is your regular fraction, see if you can finish it

OpenStudy (nicholausblackmon):

cross multiply?

OpenStudy (nicholausblackmon):

14/18 which equals what

OpenStudy (nicholausblackmon):

Its A

OpenStudy (nicholausblackmon):

7/9

OpenStudy (anonymous):

14/18=7/9

OpenStudy (anonymous):

@ganeshie8 okay i got it lol its A

OpenStudy (anonymous):

Yes, that's right.

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