i really need help with this math problem
@iGreen
Hello, are you able to set it up?
We have to evaluate \[\frac{ x }{ y }\] and are given \[x = \frac{ 2 }{ 3 },~~ \text{and}~~ y =\frac{ 6 }{ 7 }\]
So give me your best attempt at setting it up and we will go from there :)
well im not good with this one so >>.
That's alright, just give it a try, don't be afraid to mess up, I don't judge, I'm here to help!
Can you do \(x\cdot y\)?
Can you find \(1/y\)?
y=9x over 7 :< idk
does anyone know the answer ??
i wish i knew it .:0
Not quite, all you really have to do is plug x where x is in the equation x/y and do the same thing for y. So, \[\huge \frac{ x }{ y } \implies \frac{ \left( \frac{ 2 }{ 3 } \right) }{ \left( \frac{ 6 }{ 7 } \right)}\]
Don't worry about the answer right now, try understanding the process and what it's asking.
okay :) so i need to ..
So, when you first learn about fractions, do you remember what they tell you when you want to divide them?
yes :)
Alright, so what do they tell you? :)
well don't you have to divide both ,..... right
they tell you about pies and cakes to increase your appetite
well now i know its either A OR B correct ?
^ lol, but I was looking for, when you divide fractions, you flip it and multiply, so \[\huge \frac{ x }{ y } \implies \frac{ \left( \frac{ 2 }{ 3 } \right) }{ \left( \frac{ 6 }{ 7 } \right)} \implies \frac{ 2 }{ 3 } \times \frac{ 7 }{ 6 }\]
Are you able to finish it off?
flip the second fraction*
im really slow in math
after that they feed you the poison : divding two complex fractions is same as multiplying the first fraction and reciprocal of second fraction
so i think i got it . its B yea , nO?
It's ok if you're "slow" at math, it requires practice and the first step is to attempt the problem. How did you get B?
well when i multiply the fractions it = 4 over 7 so thats just a bad guess
thats a very good wrong guess, you just forgot flipping the second fraction
\[\huge \frac{ x }{ y } \implies \frac{ \left( \frac{ 2 }{ 3 } \right) }{ \left( \frac{ 6 }{ 7 } \right)} \implies \color{red}{\frac{ 2 }{ 3 } \times \frac{ 7 }{ 6 }} \]
can you work that multiplication ? to multiply two fractions, you just multiply numerators and denominators separately
\[\large \dfrac{a}{b}\times \dfrac{c}{d} = \dfrac{a\times c}{b\times d}\]
okay step by step first thing . i want to get this question right :)
@NicholausBlackmon
\[\huge \begin{align} \frac{ x }{ y } \implies \frac{ \left( \frac{ 2 }{ 3 } \right) }{ \left( \frac{ 6 }{ 7 } \right)} &\implies \color{red}{\frac{ 2 }{ 3 } \times \frac{ 7 }{ 6 }}\\~\\~\\ &\implies \color{red}{\dfrac{2\times 7}{3\times 6}} \end{align}\]
now it is your regular fraction, see if you can finish it
cross multiply?
14/18 which equals what
Its A
7/9
14/18=7/9
@ganeshie8 okay i got it lol its A
Yes, that's right.
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