Question

Are these equal values?

Answer 1

\[\int\limits_{0}^{3} \sqrt{1+\frac{ x }{ 3 }} dx =? (\frac{ 1 }{ 3 })\int\limits_{0}^{3} \sqrt{u}du\]

Answer 2

or should it be 3

Answer 3

you need to fix the bounds on right hand side

Answer 4

also the differential doesn't look correct

can you show your work ?

Answer 5

i agree with ganeshie8

Answer 6

I think that the proportionality coefficient is:
\[x=\frac{ \ln(1+\sqrt{2})+\sqrt{2} }{ 3\sqrt{3} }\]