Question

Roy exclaims that his quadratic with a discriminant of −9 has no real solutions. Roy then puts down his pencil and refuses to do any more work. Create an equation with a negative discriminant. Then explain to Roy, in calm and complete sentences, how to find the solutions, even though they are not real

Answer 1

@Pico33

Answer 2

@princeharryyy

Answer 3

Soory man I could have helped u but its 5 am morning... I should sleep... :)
bieee .. ) hope some1 will help u ...

Answer 4

Sorry*

Answer 5

You are going to need to use your own words on this one bud, your teachers can check if its from the internet

Answer 6

i know i will jus tell me what to do and i will rearrange the words to be my own

Answer 7

\[x^2-3x+3=0\]
\[discriminant=\left( -3 \right)^2-4*1*3=9-12=-3<0\]
it has no real solution.
Let us solve it by quadratic formula
\[x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]
\[x=\frac{ -\left( -3 \right)\pm \sqrt{\left( -3 \right)^2-4*1*3} }{ 2*1 }=\frac{ 3\pm \sqrt{9-12} }{ 2 }\]
\[x=\frac{ 3\pm \sqrt{-3} }{ 2 }\]

Answer 8

can you help me with about 4 more please @surjithayer