Question

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Answer 1

in the first 2sqrt15 and the second is 120sqrt15

Answer 2

so how do i get the answer?

Answer 3

zero if you use no material.

Answer 4

no thats not the answer. i have online hw and it says 120sqrt15 is wrong

Answer 5

ok i c

Answer 6

the Surface area is SA:

SA = 4(length)*(height) + (length)^2 = 300

Volume

V=(length)^2*(height)

Answer 7

@SolomonZelman @wio @iambatman @zepdrix

Answer 8

Are you taking calculus doing optimization problems?

Answer 9

yes

Answer 10

So you need to find the equation for the volume of the box and take the derivative and find the maximum point

Answer 11

Using the surface area equation and solving for height, and puting that height(h) into the volume...i get

v(L) = L * (300- L^2)

Answer 12

Find V'(L) = and set it to zero to find a maxiumum

Answer 13

V'=(300-L^2)-2L^2

Answer 14

i solved it for 0 and got 10,-10

Answer 15

\[\frac{ d }{ dL }[300L - L^3] = 300 - 2L^2 \]

Answer 16

yes, so you cant have a neg length, so L=10

Answer 17

use that in the volume or surface area equation and find the height

Answer 18

V=2000

Answer 19

L =10
H = 5

V = 500 cm^2 maximum

Answer 20

thanks

Answer 21

Thank you, that was a review for me, been like 6 yrs since calc 1. lol