Question

@DanJS

Answer 1

hi

Answer 2

hii

Answer 3

what is the reimann sum for the definite intagral

Answer 4

what..

Answer 5

can you explain how to do this prob??????

Answer 6

Which one do you want to use, the Left end point, Right, Middle?

Answer 7

left

Answer 8

Let \[\Delta x = \frac{ b-a }{ n }\]

where a and b are your interval

Answer 9

okk

Answer 10

how many boxes do they want, n=? or just leave it as a summation?

Answer 11

so you will get a bunch of rectangles with a base of \[\Delta x\]
and height \[f(a +i \Delta x) \]

Answer 12

where [a,b] is [2,5]

Answer 13

\[\sum_{i=1}^{n} f(2+i \Delta x)(\Delta x) \]

Answer 14

\[\Delta x = \frac{ b-a }{ n }\]

Answer 15

So the answer is the third one, THe area lis the limit of the sum as i --> infinity

Answer 16

wait

Answer 17

got it, thanks so much (:

Answer 18

ok yeah you get it correct?

Answer 19

i have a couple more questions to answer, ill let you know(:

Answer 20

\[\Delta x = \frac{ 3 }{ n }\]

Answer 21

it is the last answer

Answer 22

here i will type it out

Answer 23

okayy

Answer 24

\[f(x) = x^3\]

\[\lim_{n \rightarrow \infty } \sum_{i=1}^{n}f(a + i \Delta x)( \Delta x)\]

Answer 25

that is the function and the definition of the left end point reiman sum

Answer 26

got it(:

Answer 27

\[\Delta x = \frac{ b-a }{ n } = \frac{ 5-2 }{ n } = \frac{ 3 }{ n }\]

Answer 28

\[f(a+i \Delta x) = f(2 + \frac{ 3i }{ n })\]

Answer 29

f(x) = x^3

\[\lim_{n \rightarrow \infty}\sum_{i=1}^{n} (2+\frac{ 3i }{ n })^3 \frac{ 3 }{ n }\]

Answer 30

see all that?

Answer 31

i totally forgot how to do it, i had to turn to the page in my old calc book. lol

Answer 32

hahahh thank you so much you helped a lot

Answer 33

np, same process for a different interval [a,b] and function f(x)

Answer 34

For the left end point, where n = number of boxes you create under the curve

Answer 35

and as n goes off to infinity, the sum approaches the area under the curve exactly