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Mathematics 22 Online
OpenStudy (anonymous):

Which equations show that the set of whole numbers is closed under addition? Choose all answers that are correct. A. 0 + (–1) = –1 B. 1 + 1 = 2 C. 2 + 0 = 2 D. 2 + (–1) = 1

OpenStudy (anonymous):

im thinking c and a

jimthompson5910 (jim_thompson5910):

The set of whole numbers is this set: {0, 1, 2, 3, 4, 5, ...}

jimthompson5910 (jim_thompson5910):

basically nonnegative integers

jimthompson5910 (jim_thompson5910):

Closure under addition means that you take two numbers from that set and add and you should get a number in that same set as a result.

OpenStudy (anonymous):

ik but, can u give a ex. :)

jimthompson5910 (jim_thompson5910):

for example, the numbers 3 and 5 are in that set, add them 3+5 = 8 8 is also in that set as well

OpenStudy (zzr0ck3r):

none of these equations show that the whole numbers are closed

OpenStudy (anonymous):

ok.

OpenStudy (zzr0ck3r):

2 of them hint at it I guess...

OpenStudy (zzr0ck3r):

but to be closed you need to show it is true for ANY two numbers in the set, so it would take a very long time to do that if we were to check case by case.

jimthompson5910 (jim_thompson5910):

I think they just mean particular examples. Not in general.

jimthompson5910 (jim_thompson5910):

A more rigorous proof would be needed to prove it in general.

OpenStudy (anonymous):

,yea

OpenStudy (anonymous):

the more i think of it its prob. not c or a

OpenStudy (anonymous):

could be idk.

jimthompson5910 (jim_thompson5910):

well it's definitely not A why not? because -1 is not part of the set that I wrote out above

OpenStudy (anonymous):

ok so not a. could be c and d

OpenStudy (anonymous):

yesssssssssssssssssssssssssssssssssssssssssss i got a 80%

OpenStudy (zzr0ck3r):

we are not here to take a test for you.

OpenStudy (anonymous):

ok srry

OpenStudy (some.random.cool.kid):

@zzr0ck3r that doesnt mean we cant help them with test

OpenStudy (zzr0ck3r):

Just making sure the user knows

OpenStudy (anonymous):

i dont know i just started here

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