Question

The distance traveled, in feet, of a ball dropped from a tall building is modeled by the equation d(t) = 16t2 where d equals the distance traveled at time t seconds and t equals the time in seconds. What does the average rate of change of d(t) from t = 2 to t = 5 represent?

Answer 1

use the difference formula. \[D(t) = d(t2)-d(t1)/(t2-t1)\]

Answer 2

@maggie/tiffanie you got this ?
you want to compute \[\frac{16\times 5^2-16\times 2^2}{3}\]