Question

Bill wants to factor x2 + 8x + 16 by grouping; however, Sara says it is a special product and can factor a different way. Using complete sentences, explain and demonstrate how both methods will result in the same factors.

Answer 1

@surry99

Answer 2

looks like you have some help on the way

Answer 3

yes hopefully but can you stick around because i have two more? @surry99

Answer 4

@surry99 im gonna post this one next can you review it for me please
Given the function f(x) = 4(x + 1)2 − 3, indicate the shifts that will affect the location of the vertex, and explain what effect they will have. Use complete sentences.

f(x−2)
f(x) − 2
f(2x)
2•f(x)

Answer 5

f(x) =4(x+1)^2-3

Answer 6

where those question marks are that is a minus

Answer 7

"By grouping" implies the method of decomposition. Example: Factor\[x ^{2}+6x+9\]First we find that the two integers with a product of 9 and a sum of 6 are 3 and 3. Hence\[x ^{2}+6x +9\]\[=x ^{2}+3x +3x +9\]\[=x(x +3)+3(x +3)\]\[=(x +3)(x +3)\]\[=(x +3)^{2}\]

Answer 8

The other method is recognizing a trinomial as a perfect square trinomial. If given\[ax ^{2}+bx +c\]Where a and c a re both perfect squares and b (regardless of the sign) is twice the product of the square roots of a and c, then\[ax ^{2}+bx +c =(a +b)^{2}\]OR\[ax ^{2}-bx +c =(a -b)^{2}\]

Answer 9

so the first one is an answer?

Answer 10

What do you mean by "the first one is an answer"?

Answer 11

the grouping way?

Answer 12

thats how i would do it

Answer 13

That is the grouping way but that was an example, not the specific answer to your question. I expect you to follow the example and solve your own questions.

Answer 14

Yes! That is how you would do it!

Answer 15

ok can you look at the second one i posted please ima open a new question

Answer 16

Not able to read the entire question. I think you need to type it out in its entirety or provide a link if one exists.

Answer 17

ok ima repost it ok!