Question

find the equation of a line that passes through (2,8) and is parallel to y=3x+7

Answer 1

parallel lines have same slope

Answer 2

slope intercept form
y-y1=m(x-x1) (x,y) =(2,8) m=slope => 3 because it is parallel
y-8=3(x-2)

Answer 3

could you solve from there
by distributive property

Answer 4

so would it be y=3x-6

Answer 5

don't forget the 8
y-8=3(x-2)

Answer 6

y-8=3x-6

Answer 7

y=3x+2

Answer 8

point slope form
\[y - y _{1} = m( x -x _{1})\]
slope intercept form is
y = mx + b

Answer 9

yes! good job :)

Answer 10

@aaliyahfairgood but I thought the slope had to be 3?

Answer 11

nvm it is lol, I just had a dumb moment.

Answer 12

y=mx+b
y is the line
m is the slope
m=3
x is multiplied by the slope
b is the y intercept

Answer 13

@aaliyahfairgood would you be able to help me solve this one?

Answer 14

yeah sure

Answer 15

I think the slope would be -5? but I'm not sure where to go from there.

Answer 16

y-y1=m(x-x1) (x,y) =(7,-1) m =-5/1 (or just-5) because perpendicular lines are negative reciprocals
y-7=-5(x-(-1)) negative times negative equal a positive
y-7=-5(x+1)
y-7=-5x-5

Answer 17

y=-5x+2?

Answer 18

yes you got it :)

Answer 19

good job