Question

http://gyazo.com/071d292e77e3553bb89bfe2b44fa07da help please

Answer 1

explain it as well

Answer 2

to start
surface area of a pyramid, S = B + 1/2 P*l
and the volume of a pyramid, V = 1/3 B h
B = area of the base
P = perimeter
h = height
l = slant height

Answer 3

and this is asking for a lateral area

Answer 4

then you do b x i +h / p

Answer 5

to find the slant height of the pyramid use pythagorean theorem
l^2 = h^2 + (1/2 s)^2 for this problem h = 6 and s = 4
l = rt of {(6)^2 + (1/2*4)^2}= 36 +4 = rt of 40 = 6.32
the area of each lateral face is 1/2(base of lateral face)(slant height) = (1/2) (4)(6.32)=
there are 4 lateral faces
area = 4*12.64 = 50.56
to the nearest whole number = 51

Answer 6

explanation
the formula for the area of a lateral face of a pyramid is 1/2(base of face)(slant height)
there are 4 lateral faces so total area = 2 (base of face)*slant height
use pythagorean theorem to find the slant height, l given the height, h and the side, s
l^2 = h^2 + (1/2s)^2
A = 2 s l
for this problem given s = 4 and h = 6
l = 6.32
A = 2*4*6.32 = 50.56
rounded to whole number = 51
unit of measure for area given the length in m = m^2