Help on this one too? "Find 'all' of the solutions for the following equation: 2cosx - 1 = 0"
Cos x=1/2 Right?
sure? I honestly don't know.
\[x = \cos^- 1/2\]
to check this substitute that value with x \[2 \cos ( \cos^- 1/2) -1 = 0 \]
if the final answer is 0 = 0 , then it is a solution
ok, so if I'm finding all solutions, would the only solution be 0?
2cos x=1 Right?
It depends on what your given is equated to in this case it is equated to 0 , so to know if it is a solution substitute values and put them in calculator , if the result is 0 in your calculator and the given is equated to zero. It is a solution This also applies to whatever your given is equated to., for example if it is equated to 1 result should be 1 , and 1 is equal to 1, 1=1 therefore it is a solution
@babygabe97 please note that: |dw:1418570659969:dw|
ok, I see now.
Feel free to ask if u hv any confusion
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