Suppose you roll a six-sided die two times hoping to get two numbers whose sum is even. What is the sample space? How many favorable outcomes are there?
wouldnt it be 18/36
i just need clarification
@AriPotta those possibilities are not equally likely
it is true that the sample space is { 2,3,4,5,6,7,8,9,10,11,12} , but the sample points are not equally likely.
you want to know probability of rolling a sum of 2,4,6,8,10,12 you can use a diagram of the sum of two die , we can google an image
P( roll 2) = 1/36 P(roll 4) = 3/36 P( roll 6) = 5/36 P(roll 8) = 5/36 P( roll 10) = 3/36 P( roll 12) = 1/36 now add up these probabilities
18/36?
or 1/2
would that be the sample space or number of favorable outcomes
I used the modified sample space , weighting the sample points
so what would be the number of favorable outcomes?
@perl
if you want to use the original 36 point sample space, then you would have 18 favorable, and 36 total
original 36 point sample space S = { (1,1) (1,2) (2,1) (1,3) (2,2) (3,1) ...}
then the favorable events are (1,1) (1,3) (2,2) (3,1) ... those that add to an even number
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