Polygons A, B, and C are squares and intersect at the vertices. If the area of C is 676 in2 and the side length of B is 10 in , find the side length of each side in square A.
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OpenStudy (anonymous):
OpenStudy (anonymous):
@hartnn
OpenStudy (anonymous):
|dw:1418571689014:dw|
OpenStudy (anonymous):
@AriPotta
OpenStudy (aripotta):
what's the square root of 676?
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OpenStudy (anonymous):
26
OpenStudy (aripotta):
well, i was hoping 123 would answer
OpenStudy (anonymous):
aha my bad
OpenStudy (aripotta):
but yes, it's 26. and now that we know that, we know that a right triangle has a leg of 10 and a hypotenuse of 26. so we can use the Pythagorean theorem to fin the side of square a
OpenStudy (aripotta):
find*
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OpenStudy (anonymous):
yeah idk how to even use the Pythagorean theorem an im in 9th grade anit that sad aha
OpenStudy (aripotta):
lol :) the Pythagorean theorem is a^2 + b^2 = c^2. where a and b are the legs of a right triangle and c is the hypotenuse
OpenStudy (aripotta):
well i have to go. you can solve it from here :)
OpenStudy (anonymous):
OK. Sorry, my computer froze for a few minutes.
OpenStudy (anonymous):
Thanks, though, Ari! You're the best :-)
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OpenStudy (anonymous):
a^2+10^2=√26
OpenStudy (anonymous):
@satellite73
OpenStudy (anonymous):
Is the answer 26 in?
OpenStudy (anonymous):
@hartnn
OpenStudy (anonymous):
@paki
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OpenStudy (anonymous):
@mathgirl2012
OpenStudy (anonymous):
@Loser66
OpenStudy (anonymous):
Is the answer 26 in?
OpenStudy (loser66):
|dw:1418578101953:dw|
OpenStudy (loser66):
then, the leftover is \(\sqrt{26^2-10^2}\) =24
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