Question

The graph of f is shown. Evaluate eachintegral by interpreting it in terms of areas.?http://facultypages.morris.umn.edu/~mcquarrb/teachingarchive/M1101/HW/5.2.pdf
question number(5.2.33(a))

Answer 1

answer is 4

Answer 2

the \(-6\) because the first six little squares are below the x axis

Answer 3

let me look again

Answer 4

ok :)

Answer 5

i am sticking with my answer

Answer 6

hmmm

Answer 7

answer is 4 in the text book

Answer 8

i count 6 squares below the x axis, 4 above including the two triangles
this looks like a homemade book
i will stick with -2 unless maybe 4 is the answer to say b or c

Answer 9

ok you win it is 4

Answer 10

in the website, it says 4 as well

Answer 11

i am being stupid

Answer 12

i am not sure why i counted the stuff below
it is 4 by counting the squares

Answer 13

so i just have to count the squares?

Answer 14

that is all

Answer 15

well also the area of the triangles

Answer 16

could you explain it to me step by step

Answer 17

ok let me draw a lousy picture

Answer 18

from 0 to 2 above the x axis there are 3 1 by 1 squares and two triangle with area \(.5\) each for a total of 4

Answer 19

thank you

Answer 20

kind of a lousy picture, but i hope you get the idea
imagine shading that region and computing its area

Answer 21

yw, sorry i steered you wrong
can you get the next one?

Answer 22

ummm

Answer 23

i just look at the y-axis. it starts at 1 and ends at 3 in[0,2]

Answer 24

i added 3 +1/2=2

Answer 25

\[\int_0^5f(x)dx\] look at the area from x = 0 to x = 5

Answer 26

ok i will try that problem

Answer 27

it is a matter of adding up the areas of the squares and the triangles

Answer 28

hmm

Answer 29

is it 1

Answer 30

oh no

Answer 31

unless you meant 10

Answer 32

:(

Answer 33

i guess you meant 1 damn

Answer 34

lets go slow

Answer 35

i feel dumb

Answer 36

lol don't feel dumb now
feel dumb when you go "oh really, that is all?!" in a second or two