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Calculus1 11 Online
OpenStudy (anonymous):

Is this correct?

OpenStudy (anonymous):

f(x) = x^y

OpenStudy (anonymous):

ln(f(x)) = yln(x)

OpenStudy (michele_laino):

that's right!

OpenStudy (anonymous):

taking the derivative of both sides f'(x)/f(x) = y/x + ln(x)

OpenStudy (anonymous):

f'(x) = f(x) * (y/x + ln(x))

OpenStudy (anonymous):

f'(x) = (x^y)((y/x)+ln(x))

OpenStudy (michele_laino):

is y=y(x)?

OpenStudy (anonymous):

oh

OpenStudy (anonymous):

nvm

OpenStudy (anonymous):

This is part of a larger question, but I got it now.

OpenStudy (michele_laino):

I think, that: \[\frac{ f'(x) }{ f(x) }=y'(x)\ln y+\frac{ y }{ x }\]

OpenStudy (michele_laino):

so: \[f'(x)=f(x)[y'(x)\ln x+\frac{ y }{ x }]\]

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