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Calculus1
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f(x) = x^y
ln(f(x)) = yln(x)
that's right!
taking the derivative of both sides f'(x)/f(x) = y/x + ln(x)
f'(x) = f(x) * (y/x + ln(x))
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f'(x) = (x^y)((y/x)+ln(x))
is y=y(x)?
oh
nvm
This is part of a larger question, but I got it now.
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I think, that: \[\frac{ f'(x) }{ f(x) }=y'(x)\ln y+\frac{ y }{ x }\]
so: \[f'(x)=f(x)[y'(x)\ln x+\frac{ y }{ x }]\]
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