Question

The average kinetic energy of 1 mole of a gas at 102 degrees Celsius is:

4.62 x 10^1 J
1.27 x 10^3 J
2.08 x 10^3 J
4.68 x 10^3 J

Answer 1

\(\sf \large KE_{avg}=\dfrac{3}{2}kT\)

k is bolztmann's constant
T in in Kelvin here, so you need to convert.

\(\sf \large KE_{avg}=\dfrac{3}{2}k(T+273^oC)K\)