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Mathematics 20 Online
OpenStudy (anonymous):

pre calc help important!!

OpenStudy (anonymous):

state the vertical asymptote of the rational function. f(x) = (x-3)(x+4)/x^2-1

OpenStudy (solomonzelman):

\(\large\color{black}{ f(x)= \frac{\LARGE (x-3)(x+4)}{\LARGE x^2-1} }\)

OpenStudy (solomonzelman):

right?

OpenStudy (anonymous):

yes

OpenStudy (solomonzelman):

So, we are just doing a basic observation of the domain. You know that: \(\large\color{black}{ x^2-1 \ne 0 }\) right?

OpenStudy (anonymous):

yes

OpenStudy (solomonzelman):

so what is the restriction for x. What x cannot equal?

OpenStudy (anonymous):

x can't equal 0?

OpenStudy (solomonzelman):

\(\large\color{black}{ x^2-1=0 }\) solve for x.

OpenStudy (anonymous):

x^2=1

OpenStudy (solomonzelman):

and x is equal to?

OpenStudy (anonymous):

x=3 and x=-4

OpenStudy (solomonzelman):

wait,. if x^2=1, then x=? (there are 2 solutions)

OpenStudy (solomonzelman):

these solutions are the vertical asymptotes.

OpenStudy (solomonzelman):

take the square root fo each side.

OpenStudy (anonymous):

what do you mean square root of each side why wouldn't the answer be 3 and -4?

OpenStudy (solomonzelman):

\(\large\color{black}{ x^2-1 =0 }\) \(\large\color{black}{ x^2=1 }\) \(\large\color{black}{ x=? }\)

OpenStudy (solomonzelman):

(we are not finding when the function is a zero, we are finding the undefined values for the denominator)

OpenStudy (anonymous):

oh +/-1

OpenStudy (solomonzelman):

Yes. \(\large\color{black}{ \pm 1 }\)

OpenStudy (anonymous):

thanks! can u help me with 1 more problem

OpenStudy (solomonzelman):

So your vertical asymptotes are: \(\large\color{black}{ x=1 }\) and \(\large\color{black}{ x=-1 }\)

OpenStudy (solomonzelman):

I can try;)

OpenStudy (solomonzelman):

but in a different question.

OpenStudy (anonymous):

why a different one? why not just on here

OpenStudy (solomonzelman):

Well, I don't mind, but the rules of this website are that you can ask as many questions as you need, but you should ask one question per post.

OpenStudy (solomonzelman):

One reason I can think of, is thta the thread shouldn't have a very slow loading time.

OpenStudy (solomonzelman):

you can ask it here for now though

OpenStudy (anonymous):

State the horizontal asymptote of the rational function. f(x) = x+9/x^2+2x+3

OpenStudy (solomonzelman):

I wouldn't call x=0 an asymptote, well, take a look here. https://www.desmos.com/calculator/iukundkwss

OpenStudy (anonymous):

i'm solving for y

OpenStudy (solomonzelman):

I think it is just y=0, if any horizontal asymptote.

OpenStudy (solomonzelman):

I meant y initially, but wrote x-:(

OpenStudy (anonymous):

oh ok. the answer choices are y = x None y = 0 y = 9

OpenStudy (solomonzelman):

y=0 seems to be it

OpenStudy (anonymous):

ok thanks

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