Three numbers are extracted randomly from the set {1,2,3, ..., 40}. What is the probability that the product of the extracted numbers is an odd number?
First of all, figure out the general rules for multiplying odd/even numbers
well the probabilty of this becoming an odd number is to... yeah what wio said
For example \(2n\times 2m = 4mn = 2(2mn)\) so even times even is even
Odd times odd is odd. Even times odd is even.
So, even there is even one even number, the whole product is even
So the question simplifies to: What is the probability that all numbers selected are odd.
@pain100 Have I helped enough, or shall I continue?
aaaaaa..... i dont get it at all sorry
What do you not understand?
it seas ,Three numbers are extracted randomly,then what is the probability that the product of the extracted numbers is an odd numberand i dont know how to write this down
Okay, do you know what a product is?
yea
An example is if they took out 1, 2, and 3.
The product would be 6, which is even
yea,but how many combinations do i have to do to answer this,isnt there a formula or something
i need to find the odd numbers,and there are soo many combinations
Okay sure...
But my point is, if you want the product to be odd, all the numbers you pick need to be odd. Does that make sense?
This will help us solve the problem
yea,i get than,but i dont pick the numbers,they are randomly extracted
Now, how many numbers are there in the set in total?
40
How many of the numbers in it are odd?
20 i think
So what is the probability of picking one odd number?
20/40
Now, suppose we already take out an odd number. What are the total numbers in the set, and how many are odd?
19
and the total numbers in the set?
39
So, after we pick out and odd number, what is the probability that the second one we pick will be odd?
19/39
Yes, and for the third one?
and the third 18/38
So, what is the probability that all three of these events happen, and we pick 3 odd numbers?
(20/40)*(19/39)*(18/38)
So in the end, you are able to do the problem.
There wasn't any set formula... you had to be a bit clever. That is all
thanks
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