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Mathematics 7 Online
OpenStudy (anonymous):

Three numbers are extracted randomly from the set {1,2,3, ..., 40}. What is the probability that the product of the extracted numbers is an odd number?

OpenStudy (anonymous):

First of all, figure out the general rules for multiplying odd/even numbers

OpenStudy (some.random.cool.kid):

well the probabilty of this becoming an odd number is to... yeah what wio said

OpenStudy (anonymous):

For example \(2n\times 2m = 4mn = 2(2mn)\) so even times even is even

OpenStudy (anonymous):

Odd times odd is odd. Even times odd is even.

OpenStudy (anonymous):

So, even there is even one even number, the whole product is even

OpenStudy (anonymous):

So the question simplifies to: What is the probability that all numbers selected are odd.

OpenStudy (anonymous):

@pain100 Have I helped enough, or shall I continue?

OpenStudy (anonymous):

aaaaaa..... i dont get it at all sorry

OpenStudy (anonymous):

What do you not understand?

OpenStudy (anonymous):

it seas ,Three numbers are extracted randomly,then what is the probability that the product of the extracted numbers is an odd numberand i dont know how to write this down

OpenStudy (anonymous):

Okay, do you know what a product is?

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

An example is if they took out 1, 2, and 3.

OpenStudy (anonymous):

The product would be 6, which is even

OpenStudy (anonymous):

yea,but how many combinations do i have to do to answer this,isnt there a formula or something

OpenStudy (anonymous):

i need to find the odd numbers,and there are soo many combinations

OpenStudy (anonymous):

Okay sure...

OpenStudy (anonymous):

But my point is, if you want the product to be odd, all the numbers you pick need to be odd. Does that make sense?

OpenStudy (anonymous):

This will help us solve the problem

OpenStudy (anonymous):

yea,i get than,but i dont pick the numbers,they are randomly extracted

OpenStudy (anonymous):

Now, how many numbers are there in the set in total?

OpenStudy (anonymous):

40

OpenStudy (anonymous):

How many of the numbers in it are odd?

OpenStudy (anonymous):

20 i think

OpenStudy (anonymous):

So what is the probability of picking one odd number?

OpenStudy (anonymous):

20/40

OpenStudy (anonymous):

Now, suppose we already take out an odd number. What are the total numbers in the set, and how many are odd?

OpenStudy (anonymous):

19

OpenStudy (anonymous):

and the total numbers in the set?

OpenStudy (anonymous):

39

OpenStudy (anonymous):

So, after we pick out and odd number, what is the probability that the second one we pick will be odd?

OpenStudy (anonymous):

19/39

OpenStudy (anonymous):

Yes, and for the third one?

OpenStudy (anonymous):

and the third 18/38

OpenStudy (anonymous):

So, what is the probability that all three of these events happen, and we pick 3 odd numbers?

OpenStudy (anonymous):

(20/40)*(19/39)*(18/38)

OpenStudy (anonymous):

So in the end, you are able to do the problem.

OpenStudy (anonymous):

There wasn't any set formula... you had to be a bit clever. That is all

OpenStudy (anonymous):

thanks

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