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Geometry 11 Online
OpenStudy (anonymous):

If the radius of A is 5 units, calculate the area. ( The file is attached below)

OpenStudy (anonymous):

OpenStudy (jtvatsim):

Are we looking for the shaded portion? Is that the area in question?

OpenStudy (anonymous):

Yeah I think so.

OpenStudy (anonymous):

I know how to find the area of the circle, but I don't know how to find the area of triangles.

OpenStudy (jtvatsim):

neither do I... I'm trying to see how that might be done...

OpenStudy (jtvatsim):

Is there anything about the triangles being equilateral?

OpenStudy (anonymous):

oh yeah I think we need more information to get this done. Does anyone know how to solve this question?

OpenStudy (anonymous):

Umm I think the triangles could be isoscles.

ganeshie8 (ganeshie8):

try to deform the triangles inside circle into a simpler shape

OpenStudy (anonymous):

What do you mean by that? How do I deform the triangles?

OpenStudy (anonymous):

He means moving the point \(D\) up or down until you get a simpler shape

OpenStudy (anonymous):

The problem seems to imply that it doesn't matter how far A is from D

OpenStudy (anonymous):

Do you think that it's realted to the measure of arc?

OpenStudy (anonymous):

|dw:1418608699548:dw|

OpenStudy (jtvatsim):

How do we know that the angle is a right angle?

OpenStudy (jtvatsim):

But aren't those right angles related to B and C, or are you saying that they merge with D?

ganeshie8 (ganeshie8):

yeah i think we have moved the point D to A maintaining the perpendicularity with the chords

OpenStudy (jtvatsim):

ok, let's grant that... that seems reasonable.

OpenStudy (anonymous):

There are 5pi, 50pi, 10pi, and 25 pi following answers for this question

ganeshie8 (ganeshie8):

On second thoughts, i dont see how the chords could be perpendicular to each other

ganeshie8 (ganeshie8):

is it given that GH || EF ? @Korean

OpenStudy (jtvatsim):

you are right @ganeshie8, I constructed a geogebra app and the area of the triangles is not invariant with respect to D. :(

ganeshie8 (ganeshie8):

yeah i noticed the same thats the reason deleted my earlier wrong comment

OpenStudy (jtvatsim):

I really hope they are not just asking for the area of the circle :p

ganeshie8 (ganeshie8):

lol yeah options look too suspicious There are 5pi, `50pi`, 10pi, and `25 pi` following answers for this question we can eliminate 50pi and 25pi if our goal is shaded region

OpenStudy (mathmath333):

here is a similar one http://openstudy.com/study#/updates/520b190ee4b07b0d8c1d64e6

ganeshie8 (ganeshie8):

hm answer should be of form : `25pi - something`

OpenStudy (jtvatsim):

which implies that the triangles would require an irrational area ???

OpenStudy (jtvatsim):

I mean, theoretically possible, but what a nasty problem if that is really the case! :)

ganeshie8 (ganeshie8):

guess it is time to shout out `insufficient data` as the area is not invarient when we deform the triangles preserving the given conditions

OpenStudy (jtvatsim):

@Korean, if you end up finding the "answer", message me, I'll be curious to know what data we were missing ... :)

OpenStudy (anonymous):

Thank you guys though. I think the answer is 25 pi

OpenStudy (jtvatsim):

Sorry, couldn't be of more help. That would be the "obvious" choice, but so strange that the picture doesn't seem right...

OpenStudy (kainui):

It is impossible for the shaded region to be 25 pi since the total area of the circle is 25pi. It has to be less than that, since those two triangles have removed part of it.

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