Question

Solve the system of equations.
x + 3y = -1
2x + 2y = 6


(-4, 1)
(2, -1)
(4, -1)
(5, -2)

Answer 1

Use either elimination or substitution

Answer 2

Plug and play works too.

Answer 3

x + 3y = -1

Subtract 3y from both sides

x = -1 - 3y

Plug in for x

2(-1 - 3y) + 2y = 6


-2 - 6y + 2y = 6

Like terms

-2 -4y = 6

Add 2 to both sides

-4y = 8

Divide by -4


y = -2

Answer 4

or you could put it into a matrix and do the Gaussian elimination to obtain the raw echelon form. if you want a fancy way of doing it

Answer 5

x + 3(-2) = -1

x - 6 = -1

Add 6 to both sides

x = 5

Answer 6

So

x = 5
y = -2

(x,y)

What is the answer?

Answer 7

\[\left[\begin{matrix}1 & 3 & |-1\\ 2 & 2 & | \; \; \; \; 6\end{matrix}\right]\]

Answer 8

(5,-2) Thankss. I guess your explanation made it look easier than I thought it'd be hard

Answer 9

No problem! :P