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Mathematics 12 Online
OpenStudy (anonymous):

How do you set up this Exponential Equation?

OpenStudy (anonymous):

I think it is \[P(t)=Pe ^{(1/3)(30)}\] I am not sure

OpenStudy (anonymous):

A radioactive frog hops out of a pond full of nuclear waste in Oak Ridge, TN. If its level of radioactivity declines to 1/3 of the original value in 30 days, when will its level of radioactivity reach 1/100 of its original value?

OpenStudy (anonymous):

so yes you are correct

OpenStudy (anonymous):

but the tricky part is that we don't have any clear original mass number.

OpenStudy (anonymous):

so what would we do @3abf6277

OpenStudy (anonymous):

It's number 7 but I do not understand http://www.math.rutgers.edu/~sferry/MA135F14/135-f14/Final2008.pdf

OpenStudy (anonymous):

Ah I can explain

OpenStudy (anonymous):

so first we have some data: 1/3 of the original value in 30 days.

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

this is essentially a point on the graph we can plug into the question. after 30 days the FINAL value of the mass is 1/3 its original value. This is decaying at a rate that is NOT given, k which we can solve for

OpenStudy (anonymous):

So we can leave\[P = P e^((-k)(30))\] after we substitute 30 in for the time

OpenStudy (anonymous):

so its 1/3P

OpenStudy (anonymous):

yup on the left side

OpenStudy (anonymous):

then what

OpenStudy (anonymous):

Because both P's in this case are the original value, except that on the left side, it is 1/3(P), we can cancel the P's

OpenStudy (anonymous):

I think you can do the rest, theres only one variable left.

OpenStudy (anonymous):

tell me what you get as k

OpenStudy (anonymous):

then the ln in raised

OpenStudy (anonymous):

exactly you ln both sides to get rid of the e, and its simple algebra after that

OpenStudy (anonymous):

ln(1/3)/30

OpenStudy (anonymous):

I love you

OpenStudy (anonymous):

OH but hey remember, that its exponential decay, NOT exponentialy growth

OpenStudy (anonymous):

which is why there it is -k not +k

OpenStudy (anonymous):

wait so

OpenStudy (anonymous):

why does the person flip the ln(1/100)

OpenStudy (anonymous):

ok well i'm assuming you get everythign up to that point, its the same excercise essentially we did in the right side of that page. whenever you divide logarithmic equations, you divide them

OpenStudy (anonymous):

lemme get a chart of log rules

OpenStudy (anonymous):

I know but he flipped the 1/100 for no reason

OpenStudy (anonymous):

http://www.purplemath.com/modules/logrules.htm

OpenStudy (anonymous):

@3abf6277 it didnt answer my question

OpenStudy (anonymous):

so taking that example log(1/100) is also equal to log(100^-1)

OpenStudy (anonymous):

look at the bottom of the page i linked it shows the expansion rule

OpenStudy (anonymous):

that -1 can come out to the front

OpenStudy (anonymous):

seeing as (1/100) = (100)^-1

OpenStudy (anonymous):

on the first page right?

OpenStudy (anonymous):

nvm i get it

OpenStudy (anonymous):

so the power rule is it comes to the front

OpenStudy (anonymous):

exactly!

OpenStudy (anonymous):

yea in calculus remembering all those exponential rules and log rules will help alot

OpenStudy (anonymous):

you probably already know this but: http://tutorial.math.lamar.edu/ are so good. they helped me a lot when the prof or textbook wasnt

OpenStudy (anonymous):

thanks I never heard of this @3abf6277 i use khan academy

OpenStudy (anonymous):

oh dude this guys notes too: http://patrickjmt.com/

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