Mathematics
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OpenStudy (anonymous):
Where does the X come from?
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OpenStudy (anonymous):
in the answer
OpenStudy (anonymous):
y =x^(8x)
OpenStudy (anonymous):
I see that
OpenStudy (anonymous):
remember the power expansion log rule?
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OpenStudy (anonymous):
in the first step he uses that to bring the 8x down in front on the left side
OpenStudy (anonymous):
yes i understand that
OpenStudy (anonymous):
dy/dx= x^n
nx^(n-1)
OpenStudy (anonymous):
I just dont understand the second part
OpenStudy (anonymous):
I know derivative of y is 1/y dy/dx
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OpenStudy (anonymous):
but how is the derivative of 8xlnx= 8lnx+8x*1/x
OpenStudy (anonymous):
ln y =ln (x^(8x))
OpenStudy (anonymous):
ah its the chain rule!
OpenStudy (anonymous):
then
ln y =x8 ln (x)
OpenStudy (anonymous):
log rule
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OpenStudy (anonymous):
oh the product rule what a fluttering idiot
OpenStudy (anonymous):
product rule yea not chaing rule lol
OpenStudy (anonymous):
i am talking about how stupid i am
OpenStudy (anonymous):
so how does x^8x come back in the end
OpenStudy (anonymous):
he/she use the log role to solve the problem...
1- take the ln for both side... ln y =ln (x^(8x))
2-
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OpenStudy (anonymous):
wait
OpenStudy (anonymous):
I understand all the steps except the end
OpenStudy (anonymous):
I just dont understand the last step
OpenStudy (anonymous):
2- rewrite the eq. using log rule
ln y= 8x ln x
OpenStudy (anonymous):
last step puting y value
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OpenStudy (anonymous):
you're really not answering my question
OpenStudy (anonymous):
I am asking how did the x^8x appear at the end
OpenStudy (anonymous):
dy/dx (y)= 1/y y' .....
OpenStudy (anonymous):
yes i understand that step
OpenStudy (anonymous):
the y value...
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OpenStudy (anonymous):
goes to the right side i understand but in the last step it disappeared
OpenStudy (anonymous):
the Y disappeared at the end
OpenStudy (anonymous):
it goes y'=x^8x(8lnx+8)
OpenStudy (anonymous):
yes putting the value of it which is x^8x
OpenStudy (anonymous):
I finally understand
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OpenStudy (anonymous):
Thank you
OpenStudy (anonymous):
YW
OpenStudy (anonymous):
OH DUUDE, because its earlier defined as y literally equalling x^8x, you can substitute it when you move the 1/y over
OpenStudy (anonymous):
I was trying to understand that since the beginning
OpenStudy (anonymous):
i always thought of that as the last thing in my classes lol
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OpenStudy (anonymous):
lol
OpenStudy (anonymous):
i thought its history of math question -.-