simplify -2a(-7a^3+6)+(-2a)(6a^3-5)
So can you tell me the order of operations?
PEMDAS Parethesis Exponent Multiplications Division Addition Subtraction
Right..but in this case we only multiply.
And add.
ok cool so, what is the first thing you should do?
-2 times everything inside the first set of parentheses
well you have -2a
so though you could just do -2 first, why not get it all done in one shot?
So can you try distributing the -2a for me?
Let's take the first part. \(-2a(-7a^3 + 6)\) Now we distribute -2a into the parenthesis. To do that, we just multiply it to every term inside the parenthesis. \(-2a \times -7a^3 =~?\) \(-2a \times 6 =~?\) Can you multiply those?
-2a * -7a = 14a^4 -2a * 6 = -12a
No kids I'm gonna explain
It would be a^2 @TheYoungBlaze
a*a=a^2
I forgot to add the ^3 to it. It was actually -2a * -7a^3 as iGreen outlined.
So @TheYoungBlaze , though you did the multiplication correctly, you wrote the steps incorrectly. So aanyways, can you do the second part of multiplication now?
YOu got it..
My guys gotta go. My brother will help @iGreen :)
That gives us: \(-2a(-7a^3+6)+(-2a)(6a^3-5)\) \(14a^4 - 12a + (-2a)(6a^3 - 5)\) Now we distribute -2a into the parenthesis. Can you multiply these? \(-2a \times 6a^3\) \(-2a \times -5\)
-2a * 6a^3 = -12a^4 -2a * -5 = -10a
Yep, that gives us: \(14a^4-12a - 12a^4 - 10a\) Can you combine like terms? \(14a^4 - 12a^4\) \(-12a - 10a\)
14a^4 - 12a^4 = 2a^4 -12a - 10a = -22a
Yep, that gives us: \(2a^4 - 22a\) That's your final answer! :D
So its 2a^4 - 22a?
Hmm.. I double checked the original equation I posted and they're the same equation.. Idk where I went wrong?
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