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Mathematics 13 Online
OpenStudy (anonymous):

Can someone help me complete the proof?

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (xapproachesinfinity):

hmm you want to prove it is parallelogram! yes?

OpenStudy (anonymous):

Yes.

OpenStudy (xapproachesinfinity):

you need more info where are all the givens?

OpenStudy (anonymous):

Given: ΔSVX=ΔUTX and SV || TU

OpenStudy (xapproachesinfinity):

okay so we need to prove that triangle vxu is congruent to triangle sxt we already know that triangle svx is congruent to utx ============================== since we have SV||TU \(\angle SVX\equiv\angle XTU\) and \(\angle XUT\equiv\angle XST\) with \(\angle X\) share between the two triangle by the AAA postulate \(\large \triangle XUT\cong\triangle XVT\)

OpenStudy (xapproachesinfinity):

the one you have in table it is given to you right? \(\large \triangle SVX\cong\triangle UTX\)

OpenStudy (xapproachesinfinity):

i can't see what you wrote for the given i only recognized SV||TU

OpenStudy (anonymous):

it said triangle SVX = Triangle UTX

OpenStudy (xapproachesinfinity):

ok so we have that and SV||TU and we proved that triangle SVX is congruent to triangle UTX then as result the diagram is parallelogram \(\square\)

OpenStudy (xapproachesinfinity):

Do you get it!

OpenStudy (anonymous):

Not really.

OpenStudy (xapproachesinfinity):

To prove that the shape is parallelogram you need to prove that the four inside triangle are congruent (the opposing ones to each other and you need to know that two line segments are parallel and that is it

OpenStudy (xapproachesinfinity):

you are given two congruent triangles two parallel line segments we proved the other two triangles are congruent hence the shape is parallelogram

OpenStudy (anonymous):

yes, but I don't understand what to put for 2, 3, 7, and 8.

OpenStudy (xapproachesinfinity):

what's the other given? SV||TU given 3. the triangles we prove to be congruent in the reason put proved for 8 put result

OpenStudy (anonymous):

Thank You!

OpenStudy (xapproachesinfinity):

welcome

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