f(x) =sqrt x-5 find f-1
please add -1 to both sides of your equation
http://coolmath.com/algebra/16-inverse-functions/05-how-to-find-the-inverse-of-a-function-01.htm
Do you mean f(x)-1 or f^-1? :)
yes f-^1
is your function this? \[f(x)=\sqrt{x-5}\]
i think lol
Kk, yeah, then you're looking for the inverse. :) Just follow the steps in the link I posted up there. ^.^
im still confused
Kay, I'll help. Here are the steps... Step 1: Rewrite f(x) as y. y = sqrt x-5 Step 2: Switch x and y. x = sqrt y-5 Step 3: Solve for y. y = x^2 + 5 Step 4: Rewrite y as f^-1(x). f^-1(x) = x^2 + 5
A. f-1 (x) = x2 +25; 25 B. f -1 (x) = x2 + 5; y 5 C. f-1 (x) = x2 +25; 5 D. f -1 (x) = (x + 5)2; y 5
It's B. =]
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