Question

geometry proof please help picture of it in comments

Answer 1

I think that:
square is a special of parallelogram, so their diagonals have to bisect each other in the middle point.
Furthermore, diagonals of a square are equals, because a square has all its sides equals.
finally the four triangles in which our square is broken are equals each other, and inparticular angles at vertex in E have to be equals each other.
Now we have our thesis because the sum of those angles has to be equals to 360°

Answer 2

so for b i would diagonal bisectors?

Answer 3

I'm not sure, wait a moment please....

Answer 4

if DC=BC the diagonals are equal, because from DC=AB, and BC=AD I conclude that AB=AD

Answer 5

should i type all of that into the thing orrr... idk i don't understand these at all

Answer 6

I think DE=BE because diagonals in a parallelogram have to bisect each other

Answer 7

so c is diagonal bisectors but what do i put for b?

Answer 8

I think DC=BC because our geometric figure is a square

Answer 9

and we know that in a square all edges are equal

Answer 10

okay what about e

Answer 11

for the reasoning that I wrote before, namely at my first answer

Answer 12

obviously if i don't know how to do it and you don't say what things go in what spot i'm not going to understand your jumbled paragraph that was supposed to answer every question.

Answer 13

ok! then another answer is:
triangle DEC=triangle BEC, because they have all three edges equal each other neatly.
do you like it now?

Answer 14

yeah because it actually made sense

Answer 15

point f):
because since triangle BEC = triangle DEC, then they have to satisfy the first criterion of congruence.
First criterion of congruence states:
two triangles are congruent, if they have neatly congruent two edges and the angle enclosed by those edges

Answer 16

okay thanks, got it, what about h?

Answer 17

it's very simple because angle DEC and angle BEC are adiacent since they have an edge in common, so their amplitude have to sum up to 180°