Find the vertices and foci of the hyperbola with equation quantity x plus 1 squared divided by 225 minus the quantity of y plus 5 squared divided by 400 = 1.
I know what a,b,c are I just don't know how to apply it
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OpenStudy (anonymous):
@satellite73 @AccessDenied @sammixboo # @dan815
OpenStudy (anonymous):
- (y+5)^2 divided by 400 =1
OpenStudy (anonymous):
no actually \[\frac{(x+1)^2}{22
5}-\frac{(y+5)^2}{400}=1\]
OpenStudy (anonymous):
Yes thats it
OpenStudy (anonymous):
whew
you got the center right?
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OpenStudy (anonymous):
(-1,-5)?
OpenStudy (anonymous):
and also \(a==15,b=20\)
OpenStudy (anonymous):
c=25
OpenStudy (anonymous):
yeah that is right
do you know what it looks like?q
OpenStudy (anonymous):
no ;
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OpenStudy (anonymous):
|dw:1418686697354:dw|
OpenStudy (anonymous):
you need that to figure out all the rest
OpenStudy (anonymous):
horizontal
OpenStudy (anonymous):
nope first one
because the \(x^2\) term comes first
OpenStudy (anonymous):
oh okay
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OpenStudy (anonymous):
so you need the vertices right? since we now know it looks like the first one, they are 15 units to the left and right of \((-1,-5)\)