A system of equations is shown below: -3x + 7y = -16 -9x + 5y = 16 Part A: Create an equivalent system of equations by replacing one equation with the sum of that equation and a multiple of the other. Show the steps to do this. (6 points) Part B: Show that the equivalent system has the same solution as the original system of equations. (4 points)
Part A: equation (1) -3x + 7y = -16 equation (2)-9x + 5y = 16 replace (2) by adding (2) to two times (1): 2 times (1): -6x + 14y = -32 Add (2): -9x + 5y = 16 -------------------- -15x + 19y = -16 So the second pair of equations are: -3x + 7y = -16 (1) -15x + 19y = -16 (3)
I just need help with Part B
@undeadknight26 @itsbribro
i think it would be solve for 1 and 2 x,y And then solve for 1 and 3 x,y
@KlOwNlOvE i need you help
@Catlover5925 @dtuniyants @dan815
@perl
I'm not a dude -.-
okay sorry will you please help me tho.
And I have no idea how to do this, sorry
no hold on
i just need help finding x and y for -3x+y=-16 -9x+5y=16 -15x+19x=-16
-3x+7y=-16
@perl
it would be easier if you redid part a)
why was it wrong?
but if you will help me through it i will.
its not wrong, but you didn't solve for x and y
okay so we will restart where do you want to start?
actually lets keep your original work
brb
okay
so we want to show that the 'new system of equations' has the same solution as the 'old system of equations'
yes
to show that, lets plug in the solution into both system
first can you make sure my part A is correct?
ok
i had to reboot my computer , this website is super glitchy
yeah okay so can you check then go to part B?
part b) show that system : -3x + 7y = -16 -9x + 5y = 16 has same solution as system : -3x + 7y = -16 -15x + 19y = -16
yes
ok plug in x = -4, y = -4 (that is the solution for the first system )
so where do i plug it in?
for x and y
for all 4 of them?
12+(-28) 36+(-20) 60+(-76)
@perl
is that right? i checked and it was
part b) show that system : -3x + 7y = -16 -9x + 5y = 16 has same solution as system : -3x + 7y = -16 -15x + 19y = -16 Plug in (x,y) = (-4,-4) system 1: -3(-4) + 7(-4) = 12 - 28= -16 -9(-4) + 5(-4) = 36 - 20 = 16 system 2: -3(-4) + 7(-4) = 12-28 = -16 -15(-4) + 19(-4) = 60 -76= -16 so (-4,-4) is the solution for both systems. therefore the systems of equations are equivalent
Thanks so much
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