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a body oscillates in SHM according to the equation x= 5.0cos(0.40t + 0.10) find the frequency
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Your solution x(t) is the general solution to the SHM. Do you know what each term represents?
mostly
just not how to find the frequency or period
ok...the equation is of the form: x(t) = A cos(omega*t + phase angle) so what is omega from the solution?
x= 5.0cos(0.40t + 0.10) x= A cos(omega*t + phase angle) omega is...
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0.40
w=2pi/t
or w=2pif
that's correct.
then what?
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they are asking you to solve for frequency so: f = omega/2pi you now know omega
0.4 divided by 2pi?
yes indeed
thanks
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