guys this is my first time here, and i know you can help to my problems. how can i solve this one, can you show me the proper solving? f(x) = 3x⁴ -4x³ +2x ² -8x +12?

Question

anonymous · Answer

you want to find the y-intercepts of the function?

anonymous · Answer

I mean the x-intercepts, sorry

anonymous · Answer

yes

anonymous · Answer

I was trying to test the coeeficients, but that doesn't seem to give me an efficient result.

anonymous · Answer

I haven't seen such. I am not very good at math....

anonymous · Answer

uv1 + u1v

anonymous · Answer

perl [probably know.

anonymous · Answer

the formula but its hard to me to solve this

anonymous · Answer

if he doesn't reply, we can tag other people here.

anonymous · Answer

oh sure

anonymous · Answer

so you can help me right?

anonymous · Answer

I don't know how to do it-:(

anonymous · Answer

@jim_thompson5910 @Mertsj can you please help. this is not me, but still....

anonymous · Answer

jim thompson is an actual tutor, he should be able to help

anonymous · Answer

ahh, sorry this is my first time to take a calculus, :(( so its so hard to me

anonymous · Answer

we will get someone to help, patience please...

anonymous · Answer

thats why i need you help

anonymous · Answer

This is what I found, but I doubt that it's easy to read that. http://math.stackexchange.com/questions/785/is-there-a-general-formula-for-solving-4th-degree-equations

anonymous · Answer

I'll try to look for someone else, don't leave please

anonymous · Answer

@campbell_st can you help. There is some difficult problem that requires assitance.

anonymous · Answer

@Jhannybean can you help?
We are trying to find the zeros of
$$3x^4-4x^3+2x^2-8x+12~.$$

anonymous · Answer

I can't find anyone to help.... I don't even know what to do.

jim_thompson5910 · Answer

Because it's a 4th degree polynomial (a quartic), it's going to be very difficult, if not impossible, to solve by hand. So you'll have to use a graphing calculator to find the roots.

jim_thompson5910 · Answer

If you don't have a graphing calculator, you can use an online graphing calculator like desmos https://www.desmos.com/calculator

anonymous · Answer

lol all the zeros are imaginary, I checked in wolfram

anonymous · Answer

can you show me the proper way to solve?

anonymous · Answer

http://www.wolframalpha.com/input/?i=3x%5E4-4x%5E3%2B2x%5E2-8x%2B12+zeros

anonymous · Answer

I would have possible factored any integer zero, but not this way...._:(

jim_thompson5910 · Answer

yeah the whole graph is above the x axis, so it never crosses the x axis at all

anonymous · Answer

I don't think I can solve it by hand, if anyone can..... maybe there is some formula, but...

anonymous · Answer

ty for coming and checking out, though!

jim_thompson5910 · Answer

there is the quartic formula http://www.sosmath.com/algebra/factor/fac12/fac12.html but that is a very difficult formula to grasp and I'm sure it's beyond the scope of the course

anonymous · Answer

wait its that it?

jim_thompson5910 · Answer

so if you're looking for real roots, you just simply say "there are no real roots" because it doesn't cross the x axis anywhere

anonymous · Answer

ahh i see, thank you for helping bros,

anonymous · Answer

I haven't helped.

anonymous · Answer

but yw, if I did anything...

anonymous · Answer

I am also taking calc1, but I haven't ever had to do such a thing.

anonymous · Answer

thank you bro! fbi

anonymous · Answer

np

jhannybean · Answer

Sometimes in calc 1, understanding how to factor quartic functions will be necessariy when finding maximum and minimum values.