Question

please help me in diff calculus! :)) can you show the proper solving of this one? f(x) = 1/2x^2 + 3x 1/x^2? diff calculus

Answer 1

\[f(x)=\frac{1}{2}x^2+3x+\frac{1}{x^2}\] or something else?

Answer 2

yes thats it

Answer 3

ahh no

Answer 4

oops

Answer 5

yeah thats it soory

Answer 6

lol

Answer 7

you sure?

Answer 8

ahhm can you help to solve that one?

Answer 9

yeah ahhm very sure

Answer 10

i would be happy to
unfortunately you do not have a question, just a function
what is the question?
since you wrote "calc" it could be
a) graph
b) find the derivative
c) identify the critical points
d) find the anti derivative

Answer 11

i am kind of hoping it is 'find the derivative" because that would be easiest

Answer 12

my prof said we dont need to get the grapgh just derivatives only

Answer 13

so the question is
given \(f(x)=\frac{1}{2}x^2+3x+\frac{1}{x^2}\) find \(f'(x)\) right?

Answer 14

thats why its so hard to me :(

Answer 15

yeah f ^1(x)

Answer 16

repeated applications of the all mighty power rule, most easily written as
\[\frac{d}{dx}[x^n]=nx^{n-1}\]

Answer 17

ok ill get my reading glass

Answer 18

for example the derivative of \(x^7\) is \(7x^6\) and the derivative of \(x^{-3}\) is \(-3x^{-4}\)

Answer 19

\[\huge \frac{d}{dx}[x^n]=nx^{n-1}\]

Answer 20

than how can we solve if we get the proper formula?

Answer 21

i am not sure what you are asking
your job is to find the derivative right? and the tool we have at our disposal is the "power rule"
so for example the derivative of
\[\huge \frac{1}{2}x^2\]is
\[\huge 2\times \frac{1}{2}x^{2-1}=x\]

Answer 22

the derivative of \(3x\) is just \(3\) since the derivative of a line is the slope

Answer 23

the only one that requires some work is to find the derivative of \(\frac{1}{x^2}\)
to use the power rule write
\[\frac{1}{x^2}=x^{-2}\] and then use it

Answer 24

@satellite73 show me the proper, its hard to me

Answer 25

show me the proper way of salving, to easy to understand sir.

Answer 26

we take the derivative piece by piece
\[f(x)=\frac{1}{2}x^2+3x+x^{-2}\]
\[f'(x)=2\times \frac{1}{2}x^{2-1}+3x^{1-1}-2x^{-2-1}\]
\[f'(x)=x+3-2x^{-3}\]

Answer 27

so the final answr is x+3 -2x^2?

Answer 28

no but close
final ansswer is
\[x+3-2x^{-3}\] or
\[x+3-\frac{2}{x^3}\]

Answer 29

@satellite73 thank you sir .:)

Answer 30

yw
hope it helped