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Mathematics 19 Online
OpenStudy (anonymous):

Find the indicated sum. Show your work.

OpenStudy (anonymous):

OpenStudy (anonymous):

am i doing it right?

OpenStudy (jtvatsim):

Are you saying that the answer is 0?

OpenStudy (anonymous):

i dont think so :/

OpenStudy (anonymous):

with summation formula its giving 46 and 2 confuse ...

OpenStudy (jtvatsim):

OK, let's make sure you understand how summation notation works first.

OpenStudy (anonymous):

sure :) i have to show my work

OpenStudy (jtvatsim):

Could you tell me what the sum is of this question? \[\sum_{k=1}^4 2k\]

OpenStudy (jtvatsim):

If not, that is ok, I'll explain... just let me know :)

OpenStudy (anonymous):

i guess k= the limit and 4 is upper value

OpenStudy (anonymous):

yes please

OpenStudy (jtvatsim):

OK, summation notation is just shorthand... it's a compact way of writing a long addition problem.

OpenStudy (jtvatsim):

In this problem we have the scary looking sigma \[\sum\] which just means "you will add these things together"

OpenStudy (anonymous):

hmm

OpenStudy (jtvatsim):

Now, whatever is to the right of the sigma is what the numbers "look like" it is there "shape." This time they look like 2k.. That is 2 multiplied by some number.

OpenStudy (jtvatsim):

But what number should I use? And how many? This is what the "limits" tell us. Start with k = 1... and keep plugging in k's until you reach k = 4.

OpenStudy (anonymous):

OpenStudy (jtvatsim):

Of course, I'm still working on the easy problem for now... :)

OpenStudy (jtvatsim):

So, to answer the "easy" problem I gave we would simply do this \[\sum_{k=1}^4 2k = 2(1) + 2(2) + 2(3) + 2(4)\]

OpenStudy (jtvatsim):

See how the k switches each time? And we just add them together?

OpenStudy (anonymous):

ok let me try now

OpenStudy (jtvatsim):

Sure thing!

OpenStudy (anonymous):

OpenStudy (anonymous):

k will replace numbers from 1-4?

OpenStudy (jtvatsim):

Yes, good

OpenStudy (anonymous):

in bracket Ex = (-1)^1(1+11)... etc?

OpenStudy (jtvatsim):

Yes, (-1)^[1] ([1] + 11) + ... and so on.

OpenStudy (jtvatsim):

In this case, there are two k's in the "shape of the number" to replace

OpenStudy (anonymous):

after getting all that should i write the sum or different values?

OpenStudy (jtvatsim):

You should first write the whole thing out. And then add the numbers like you would any old day (simplify).

OpenStudy (jtvatsim):

So like \[\sum something = s1 + s2 + s3 + s4 = number\]

OpenStudy (anonymous):

ok ill write just give me a min

OpenStudy (jtvatsim):

Go right ahead! :)

OpenStudy (anonymous):

=(-1)^1(1+11) +(-1)^2(2+11) +(-1)^3(3+11) +(-1)^4(4+11)

OpenStudy (jtvatsim):

I like what I see so far. :)

OpenStudy (anonymous):

(-12)++(13)+(-14)+15

OpenStudy (jtvatsim):

Yep yep, looking nice.

OpenStudy (anonymous):

=2

OpenStudy (anonymous):

correct?

OpenStudy (jtvatsim):

Good, you are correct. :)

OpenStudy (jtvatsim):

The answer is plain old 2... a lot of work for an easy number huh?

OpenStudy (anonymous):

thanks alot :)

OpenStudy (anonymous):

yups :P

OpenStudy (jtvatsim):

No worries! You are welcome. Good luck with your studies!

OpenStudy (anonymous):

thanks its my last course Excited :)

OpenStudy (anonymous):

can i ask others if need to?

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