Question

tanx+sinxsecx/cscxtanx

Answer 1

Hello! Welcome to OpenStudy! Can you give us some more information about the question? Are we supposed to simplify the expression? Or something else?

Answer 2

Simplify

Answer 3

OK, that helps.

Answer 4

I'm not sure what the answer is yet, but a good trick is to rewrite everything as sin and cos. So make tan x = sin x/cos x, sec x = 1/cos x, csc x = 1/sin x...

Answer 5

I think its supposed to equle 2sinx

Answer 6

Hmm... I'm not so sure... Let's see what happens when we rewrite: \[\frac{\sin{x}}{\cos{x}} + \frac{\sin{x} \frac{1}{\cos{x}}}{\frac{1}{\sin{x}}\frac{\sin{x}}{\cos{x}}}\]

Answer 7

We can cancel the sin x on the bottom of the fraction to get: \[\frac{\sin{x}}{\cos{x}}+\frac{\sin{x}\frac{1}{\cos{x}}}{\frac{1}{\cos{x}}}\]

Answer 8

We can also cancel the 1/cos(x) since they are the same on top and the bottom \[\frac{\sin{x}}{\cos{x}}+\frac{\sin{x}(\frac{1}{\cos{x}})}{(\frac{1}{\cos{x}})}\]

Answer 9

To get \[\frac{\sin{x}}{\cos{x}}+\sin{x}\]

Answer 10

We are almost there, does that make sense so far?

Answer 11

Yes

Answer 12

Well, then, I think we are as far as we can go. We simplify sin(x)/cos(x) back to tan(x) and get \[\tan{x} + \sin{x}\] I think that is as far as we can go.