Question

what is the length of the focal width x=1/4y^2

Answer 1

@jim_thompson5910

Answer 2

x = (1/4)*y^2

4x = y^2

4(x-0) = (y-0)^2

4*1*(x-0) = (y-0)^2

Answer 3

the equation 4*1*(x-0) = (y-0)^2 is in the form 4p(x-h) = (y-k)^2

where

p is the focal distance
(h,k) is the vertex

so we can see that p = 1

Answer 4

p = 1 means that the distance from the focus to the vertex is 1 unit

Answer 5

is the focal point=1?

Answer 6

it's not at that location, but that is the focal distance

Answer 7

what is the focal width?

Answer 8

oh I'm mixing up focal distance and focal width

Answer 9

luckily the two are found using p

Answer 10

|p| = focal distance

|4p| = focal width

Answer 11

4 is the answer?

Answer 12

yes