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Suppose a normal distribution has a mean of 98 and a standard deviation of 6. What is P(x<= 104) ?
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if the raw score is x = 104, then what is the z-score?
ok then it would be 104-98=6/6=1
That means P(X <= 104) is the same as P(Z <= 1)
you would then use a table like this one http://www.stat.ufl.edu/~athienit/Tables/Ztable.pdf to find the area under the curve to the left of z = +1.00
Tell me what you get.
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.8413
very good, so because \[\Large P(Z \le 1) = 0.8413\] this means \[\Large P(X \le 104) = 0.8413\]
well both approximate, but you get the idea
ok thanks so much!!
you're welcome
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