Question

f(d)= (d^4-d+1)1/3 derivative function, please help to answer this. show me the proper wat to solve to easy to understand!

Answer 1

interesting problem :)

Answer 2

@perl can you help sir?

Answer 3

@ganeshie8 sir can you help me?

Answer 4

if i understood the problem i could help :)

Answer 5

please help me. :((

Answer 6

You are given the derivative, or you want to find the derivative?

Answer 7

find sir

Answer 8

@wio sir please help me

Answer 9

This?\[
f(d)= (d^4-d+1)^{1/3}
\]

Answer 10

yes sir

Answer 11

Do you know the chain rule?

Answer 12

no sir

Answer 13

can you show me the proper way to solve?

Answer 14

Hmm, to be honest, I'm not sure how to do this without using the chain rule.

Answer 15

Are you sure they did not teach the chian rule?

Answer 16

no my prof teach how to solve thabuy im absent always because of my nightshiht callcenter parttime

Answer 17

so i dont know how to solve that?
:'(

Answer 18

@strawberryswing help

Answer 19

@sammixboo help

Answer 20

@Zale101 help

Answer 21

Okay, what rules do you know?

Answer 22

Ahhhhhh math

Answer 23

Run!

Answer 24

@wio

Answer 25

Okay, now consider that: \[
f(d) \times f(d)\times f(d) =d^4-d+1
\]

Answer 26

You can differentiate both sides, using the product rule and power rules.

Answer 27

So \[
3(f'(d)\times f(d)\times f(d)) = 4d^3-1
\]Does this make sense?

Answer 28

yes sir

Answer 29

Now we plug in \(f(d) = (d^4-d+1)^{1/3}\)

Answer 30

So \[
f'(d) \cdot 3(d^4-d+1)^{2/3} = 4d^3-1
\]

Answer 31

Does this make sense?

Answer 32

so sir what is the final answr

Answer 33

Can you solve for \(f'(d)\)? That is what we originally wanted.

Answer 34

i dont knw how to solve that sir

Answer 35

sir?

Answer 36

It's algebra... divide the part that isn't \(f'(d)\).

Answer 37

@wio 0?