Mathematics
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OpenStudy (anonymous):
Help me please:
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OpenStudy (anonymous):
Let e1 and e2 denote the eccentricites of the hyperbolas
\[\frac{ x^2 }{ m^2 }-\frac{ y^2 }{ n^2 }=1 \]
and
\[\frac{ y^2 }{ n^2 }-\frac{ x^2 }{ m^2 }=1\]
respectively.
Verify that
\[e \left(\begin{matrix}2 \\ 1\end{matrix}\right)e \left(\begin{matrix}2 \\ 2\end{matrix}\right)=e \left(\begin{matrix}2 \\ 1\end{matrix}\right)+e \left(\begin{matrix}2 \\ 2\end{matrix}\right)\]
OpenStudy (anonymous):
@triciaal
OpenStudy (anonymous):
@wio
OpenStudy (triciaal):
not current on this, sorry
OpenStudy (anonymous):
can you tag someone who might know?
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OpenStudy (triciaal):
@satellite73, @mathstudent55, @jim_thompson5910 can you please help?
OpenStudy (anonymous):
by the way its "e sub 1 squared" incase you were confused
OpenStudy (triciaal):
@pico33 ?
OpenStudy (anonymous):
and eccentricity is basically c/a
OpenStudy (triciaal):
@jhannybean do you mind helping?
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OpenStudy (anonymous):
@ganeshie8
OpenStudy (anonymous):
@Abhisar
OpenStudy (anonymous):
@dan815
OpenStudy (anonymous):
@Compassionate
OpenStudy (triciaal):
@ganeshie8 will you please help
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OpenStudy (anonymous):
its actually
\[e_1^2e_2^2=e_1^2+e_2^2\]
OpenStudy (anonymous):
not the other one i inserted
OpenStudy (jhannybean):
Not sure about these..
OpenStudy (anonymous):
do you know anyone who would know? and if you do can you tag them please?
OpenStudy (dan815):
draw what eccentricities are
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OpenStudy (anonymous):
isnt it c/a?
OpenStudy (dan815):
whats c and a
OpenStudy (anonymous):
im trying to decide whether a is m or n
OpenStudy (anonymous):
c is \[\sqrt{m^2+n^2}\]
OpenStudy (dan815):
ok
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OpenStudy (dan815):
you should google what eccentricities of hyprbole are
OpenStudy (anonymous):
what do you mean google it? isnt it just c/a?
OpenStudy (anonymous):
so like \[\frac{ m }{ \sqrt{m^2+n^2} }\]
OpenStudy (anonymous):
@wio
OpenStudy (dan815):
ok
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OpenStudy (anonymous):
but is that e1 or e2?
OpenStudy (dan815):
lets say its e1, what is e2?
OpenStudy (anonymous):
n^2 over that number?
OpenStudy (anonymous):
so there is no way of knowing if "m" is "a" or "b"?
OpenStudy (dan815):
there is
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OpenStudy (anonymous):
how?
OpenStudy (dan815):
if u learn what eccentricities are :P
OpenStudy (dan815):
im jk
OpenStudy (anonymous):
can you help me?
OpenStudy (anonymous):
its ok
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OpenStudy (dan815):
but i think c/a
c=the hyptenues of the major and miinor length
OpenStudy (dan815):
and a= probably the major
OpenStudy (anonymous):
isnt c the distance from the center to the vertex?
OpenStudy (dan815):
yeah that is equivalent to the hyp of m and n
OpenStudy (dan815):
eccentricity tells u how curved or close to parallel the hyperbola is
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OpenStudy (anonymous):
so then how would you know which is "a" and "b"?
OpenStudy (dan815):
okay so think which one wud matter
OpenStudy (dan815):
say u have x^2/a^2-y^2/b^2=1 parabola
OpenStudy (dan815):
can u graph that
ganeshie8 (ganeshie8):
\[e_1 = \frac{c}{a} = \dfrac{\sqrt{m^2+n^2}}{m}\]
\[e_2 = \frac{c}{a} = \dfrac{\sqrt{m^2+n^2}}{n}\]
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OpenStudy (anonymous):
i dont remember how :(
ganeshie8 (ganeshie8):
plug them in the given equation and do ur algebra
OpenStudy (dan815):
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