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simplify: x^2-3x-10/x+2
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\[\frac{x^2-3x-10}{x+2}\] Try factoring the numerator.
On problems like this, the denominator is frequently a factor of the numerator. So try this: x^2-3x-10 = ( x + 2)* ( ? + ? )
(x+5)?
Close - when there are 2 minus signs in the expanded version (x^2-3x-10), then it usually means that the factorisation contains one plus and one minus.
The foolproof way of checking your answer would be to expand your roots see if it matches. Does (x+2)(x+5)=x^2-3x-10?
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@KendrickLamar2014, yes, you can...
Correct or not? |dw:1418716669601:dw|
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