Question

PLEASE HELP!!! WILL FAN AND MEDAL!!!

What is the probability that a data value in a normal distribution is between a z-score of -0.28 and a z-score of 0.64?

Answer 1

if we suppoe that \[\mu = 0 \sigma =1 \] then depending of that :-
\[\phi(0.64) - \phi(-0.28)\] = \[\phi(0.64) - ( 1 - \phi(0.28)) = \phi(0.64) + \phi(0.28) -1\] and the answer check it in the table

Answer 2

the formal answer with normal Distribution :-
P(-0.28 <z<0.64) = \[P((-0.28 -\mu )/\sigma) < ((z -\mu )/\sigma) <((0.64-\mu )/\sigma) \]\[X = ((z -\mu )/\sigma)\] X ~ Norm(0,1)

Answer 3

thanks! do you know how to find a percent for that?

Answer 4

\[0.61026 + 0.73891 -1 = 0.34917 \]

Answer 5

Thank you so much!!!