Find limit as x approaches three from the right of f of x..
The answers are: -1 7 -4 Doesn't exist I think that it's -4. Is that right?
please note that, you function can not to be made continuous at x=3!
Okay, so is my answer wrong? @Michele_Laino
yes I think!
If it's not -4, then is it -1?
no I think not!
Hmm, 7?
no I think not!
I don't understand. Does the limit not exist? Because I thought it was -4.
I think, that your limit doesn't exist, because there is no way to make your function continue at x=3
1) What is \(\Large\color{black}{\displaystyle\lim_{x \rightarrow ~3^{-}}~f(x)}\) ? 2) What is \(\Large\color{black}{\displaystyle\lim_{x \rightarrow ~3^{+}}~f(x)}\) ?
When the sides are not equivalent than the limit DNE, but in your case are they equivalent or not?
\(\Large\color{black}{\displaystyle\lim_{x \rightarrow ~3^{+}}~f(x)}\)
I am putting up more and more stuff, but can you just tell me if you know what it means to say: \(\Large\color{black}{\displaystyle\lim_{x \rightarrow ~3^{+}}~f(x)}\) ?
Yes?
Okay do you see this on the graph, do you see the point, where the function is approaching FROM THE RIGHT the point, whose x-coordinate is 3. (there are 3 points/dots with x -coordinate 3, but tell me the one that is connected to the RIGHT part of your function)
It's -4
I'l;l put up an attachment for you to better see if you want
Yes, -4
So, \(\large\color{black}{\displaystyle\lim_{x \rightarrow ~3^{+}}=-4}\)
Thank you. I thought I was going crazy for a second.
No, it is just a need of looking. can you tell me what \(\large\color{blue}{\displaystyle\lim_{x \rightarrow ~3^{-}}f(x)}\) is going to be?
Would it be 7?
sorry I'm not sure that your limit = -4, is not the right answer! because I think that, observing your graph that f(3) = 7, and y=7 is an isolated point
No, Michele, the \(\large\color{black}{\displaystyle\lim_{x \rightarrow ~3^{+}}f(x)=-4}\) is correct. The limit only, although, \(\large\color{black}{f(3)=7}\)
I think that if limit exists, then that limit has to be equals to 7, because with y=7, our function is continue in x=3
And sunshine, When I say \(\large\color{black}{\displaystyle\lim_{x \rightarrow ~3^{-}}f(x)}\) I mean, what is the y-coordinate of the point connected to the left part of the function, where the (x-coordinate 3)?
Only have to have \(\large\color{black}{\displaystyle\lim_{x \rightarrow ~3^{}}f(x)=7}\) is \(\large\color{black}{f(x)}\) is continuous at x=3.
In this case none of the conditions are mat: For it to be continuous at \(\large\color{black}{x=3}\). 1) \(\large\color{black}{\displaystyle\lim_{x \rightarrow ~3^{}}f(x)}\) Exists. 2) \(\large\color{black}{\displaystyle\lim_{x \rightarrow ~3^{}}f(x)=f(3)}\) 3) \(\large\color{black}{f(3)}\) exists --- the only condition that's there.
@SolomonZelman you are right! so requested limit is equal to 7
No
So the limit doesn't exist because both left and right don't match? One is -4 and the other is 7.
The requested limit is \(\large\color{black}{\displaystyle\lim_{x \rightarrow ~3^{+}}f(x)}\) where it APPROACHES x from the right, and that is \(\large\color{black}{-4}\)/
please y=7 is an isolated point of the image of your function
I'm majorly confused. What is the limit?? @SolomonZelman
So, that is an f(3). But it not the LIMIT. You probably have learned calculus a long time ago, it would not be bad to rvw. By no means do I mean to be rude. \(\large\color{black}{\displaystyle\lim_{x \rightarrow ~3^{-}}f(x)=1}\) \(\large\color{black}{\displaystyle\lim_{x \rightarrow ~3^{+}}f(x)=-4}\) \(\large\color{black}{f(3)=7}\) this is what we have.
Ohh, the \(\large\color{black}{\displaystyle\lim_{x \rightarrow ~3^{-}}f(x)}\) is NEGATIVE 1
@SolomonZelman please is our function continue at x=3?
No
Of course not.
wrong answer sorry!
I am not mathematician, but this I do know. Tell me, 1) Does \(\large\color{black}{\displaystyle\lim_{x \rightarrow ~3^{}}f(x)}\) EXIST? 2) Does \(\large\color{black}{\displaystyle\lim_{x \rightarrow ~3^{-}}f(x)=-4}\) ?
I get it now. The answer I needed was -4. So thanks to the both of you.
you are confusing something overhere. it is x=3 where all the discontunuity mess is going on.
Yes, you need -4:) yw
We can go over this, Michelle, if you would like to.
@SolomonZelman last question, is x=3 an isolated point?
x=3 is not a point. the POINT on the function is \(\large\color{black}{(3,7)}\). Yes, it is isolated from the rest of the f(x).
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