Find the inverse of \(f(x) = x^\frac{1}{n}\)
In the lecture notes, my teacher wrote \(f^{-1}(x) = x^n\), but isn't \(f^{-1}(f(x)) = (x^\frac{1}{n})^n = x^1 = x \ne 1\)?
re-write f(x) as y. switch the x and the y, and then solve for y after you switched x and y.
Please read my comment above
and then once you find that; which is the inverse function, write the notation \(\large\color{black}{ f^{-1}(x) }\). \(\large\color{black}{ f(x)=x^{1/n} }\) \(\LARGE\color{white}{ \rm \left| \right| }\) \(\large\color{black}{ y=x^{1/n} }\) \(\LARGE\color{white}{ \rm \left| \right| }\) \(\large\color{black}{ x=y^{1/n} }\) \(\LARGE\color{white}{ \rm \left| \right| }\) \(\large\color{black}{ x^n=y }\) \(\LARGE\color{white}{ \rm \left| \right| }\) \(\large\color{black}{ f^{-1}(x)=x^n }\) \(\LARGE\color{white}{ \rm \left| \right| }\)
this is all you need to do here.
I know how to find inverse of a function (the steps), I just misunderstood something
and include your restriction that: \(\large\color{black}{ x\ne1 }\) as the \(\large\color{black}{ f(x) }\) requires you.
Inverse of a function => \(f^{-1}(f(x)) = x\) Inverse of a number => \(f^{-1}(f(c)) = 1\)
I would think so........
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