Question

How many moles of oxygen are needed to burn 1.33 moles of methyl alcohol (CH3OH)?
2CH3OH + 3O2 2CO2 + 4H2O

Answer 1

please note that your equation can be rewritten as below:
\[CH _{3}OH+\frac{ 3 }{ 2 }O _{2}\rightarrow CO _{2}+2H _{2}O\]

Answer 2

which means that for 1 mole of aocohol we have to use 1.5 moles of oxygen, then
for 1.33 moles of alcohol, we have to use 1.5*1.33=... moles of oxygen