Question

1. Given the equation -4squrt(x-3)=12, solve for x and identify if it is an extraneous solution.
x = 0, solution is not extraneous

x = 0, solution is extraneous

x = 12, solution is not extraneous

x = 12, solution is extraneous

Answer 1

@Directrix can you help with this one? the left side is negative but the right side is positive, so there can't be a solution...?

Answer 2

@SolomonZelman please help?

Answer 3

\(\large\color{black}{ 4\sqrt{x-3}=12 }\)

Answer 4

-4

Answer 5

\(\large\color{black}{ -4\sqrt{x-3}=12 }\)


divide both sides by \(\large\color{black}{ -4 }\) .

Answer 6

can you do that for me?

Answer 7

delete this now!

Answer 8

delete?

Answer 9

not you

Answer 10

I got x = 12 but I have to run it back through the equation.

Answer 11

\(\large\color{black}{ -4\sqrt{x-3}=12 }\)

\(\large\color{black}{ \color{red}{(}-4\sqrt{x-3}\color{red}{)\div(-4)}=12\color{red}{)\div(-4)} }\)

Answer 12

Directrix since when you are giving out answers like this?

Answer 13

@Directrix but is it extraneous or not?

Answer 14

x = 12 is extraneous.

Answer 15

ok thanks!

Answer 16

when x=0 we get sqrt(-3), is this a valid operation when x=0?

Answer 17

I am not reporting, lol...

Answer 18

It is extraneous and here is why.